Franklin is a city in Franklin County, Idaho, United States. The population was 641 at the 2010 census. It is part of the Logan, Utah-Idaho Metropolitan Statistical Area.
Franklin is located at 42°0′58″N 111°48′11″W (42.016039, -111.803101). at an elevation of 4,501 feet (1,372 m) above sea level.
According to the United States Census Bureau, the city has a total area of 1.29 square miles (3.34 km²), of which, 1.26 square miles (3.26 km²) is land and 0.03 square miles (0.08 km²) is water.
As of the census of 2010, there were 641 people, 221 households, and 155 families residing in the city. The population density was 508.7 inhabitants per square mile (196.4/km²). There were 236 housing units at an average density of 187.3 per square mile (72.3/km²). The racial makeup of the city was 91.1% White, 0.5% African American, 0.5% Native American, 6.2% from other races, and 1.7% from two or more races. Hispanic or Latino of any race were 13.1% of the population.
There were 221 households of which 42.5% had children under the age of 18 living with them, 62.4% were married couples living together, 5.0% had a female householder with no husband present, 2.7% had a male householder with no wife present, and 29.9% were non-families. 26.7% of all households were made up of individuals and 12.2% had someone living alone who was 65 years of age or older. The average household size was 2.90 and the average family size was 3.61.
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